document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006133>Question 1006133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello There. I am working on rewriting logs using the power and product rules and I am having a hard time with this specific problem. Can you help me?<BR>\n" );
document.write( "Here is the problem:\r<BR>\n" );
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document.write( "log_2(16^x 5y^7) I hope it is understandable. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622275 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From what you wrote, <BR>\n" );
document.write( "log_2(16^x 5y^7), we can use the rules of logarithms to get<BR>\n" );
document.write( "x*log_2 16 + log_2 5 + 7*log_2 y = <BR>\n" );
document.write( "4x + log_2 5 + 7*log_2 y </SPAN>\n" );
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