document.write( "Question 1006121: Can you help me with my homework on Analytic Geometry, please?\r
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document.write( "Here's the given problem:\r
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document.write( "Reduce this equation to standarm form 9x^2-4y^2+36x-16y-16=0. Find also the coordinates of the center, foci, and vertices. Draw also the asymptote and sketch the graph of the equation.
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Algebra.Com's Answer #622270 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! 9x^2 -4y^2 +36x -16y -16 = 0 \n" ); document.write( "this is the equation of a hyperbola \n" ); document.write( "******************************************************************************** \n" ); document.write( "factor equation and complete the square \n" ); document.write( "9(x+2)^2 -4(y+2)^2 = 36 \n" ); document.write( "now divide both sides of = by 36 \n" ); document.write( "(x+2)^2 / 4 - (y+2) / 9 = 1 \n" ); document.write( "this is standard form for hyperbola \n" ); document.write( "******************************************************************************** \n" ); document.write( "center of hyperbola is (-2, -2) \n" ); document.write( "******************************************************************************** \n" ); document.write( "vertices are (h+a,k) and (h-a,k), (0, -2) and (-4, -2) \n" ); document.write( "******************************************************************************** \n" ); document.write( "to determine foci, first calculate c^2 = a^2 + b^2 \n" ); document.write( "c^2 = 4 + 9 \n" ); document.write( "c = sqrt(13) \n" ); document.write( "foci are (-2+sqrt(13), -2) and (-2-sqrt(13)) \n" ); document.write( "******************************************************************************* \n" ); document.write( "slope of asymptotes are + or - b/a = 9/4 and -9/4 \n" ); document.write( "equations of asymptotes are y = k + or - b/a(x-h), \n" ); document.write( "y = -2 + (9/4)(x - 2) and y = -2 - (9/4)(x - 2) \n" ); document.write( "****************************************************************************** \n" ); document.write( "here is the graph \n" ); document.write( " \n" ); document.write( "note that the left curve of the hyperbola is continuous, not sure why it is broken\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |