document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006126>Question 1006126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/a+1/p=1 solve for a </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622264 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with 1/a + 1/p = 1<BR>\n" );
document.write( "multiply both sides of the equation by ap to get:<BR>\n" );
document.write( "p + a = ap<BR>\n" );
document.write( "subtract a from both sides of the equation to get:<BR>\n" );
document.write( "p = ap - a<BR>\n" );
document.write( "factor out the a to get:<BR>\n" );
document.write( "p = a * (p-1)<BR>\n" );
document.write( "divide both sides of the equation by (p-1) to get:<BR>\n" );
document.write( "p / (p-1) = a<BR>\n" );
document.write( "your solution is:<BR>\n" );
document.write( "a = p / (p-1)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "confirm by taking any value of p at random and solving for a.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "note that this assumes that p is positive.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "it gets more complex if you assume that a or p or both can be negative.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "i don't think that they wanted it to be that complex for you so i'll assume a and p are both positive.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "we have a = p/(p-1)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "assume any positive value for p.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "we'll try 555.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "a is equal to 555/554.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1/a + 1/p = 1 becomes:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1/(555/554) + 1/555 = 1.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "since 1/(555/554) is the same as (554/555), the equation becomes:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "554/555 + 1/555 = 1 which becomes 555/555 = 1 which becomes 1 = 1.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );