document.write( "Question 1006093: The sum of the solutions of the equation (3x+2/x-2)+(1/x-1)=-1/x^2-3x+2 \n" ); document.write( "

Algebra.Com's Answer #622250 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%283x%2B2%29%2F%28x-2%29%2B1%2F%28x-1%29=-1%2F%28x%5E2-3x%2B2%29\"$
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\n" ); document.write( " $\"%283x%5E2-x-2%2Bx-2%29%2F%28%28x-2%29%28x-1%29%29=-1%2F%28%28x-2%29%28x-1%29%29\"$
\n" ); document.write( " $\"%283x%5E2-4%29%2F%28%28x-2%29%28x-1%29%29=-1%2F%28%28x-2%29%28x-1%29%29\"$
\n" ); document.write( "Which leads to,
\n" ); document.write( " $\"3x%5E2-4=-1\"$
\n" ); document.write( " $\"3x%5E2-3=0\"$
\n" ); document.write( " $\"3%28x%5E2-1%29=0\"$
\n" ); document.write( " $\"%28x-1%29%28x%2B1%29=0\"$
\n" ); document.write( "Two solutions,
\n" ); document.write( " $\"x-1=0\"$
\n" ); document.write( " $\"x=1\"$
\n" ); document.write( "However since $\"x-1\"$ and $\"x-2\"$ are in the original equation, $\"x=1\"$ and $\"x=2\"$ are not allowed solutions since they would lead to a division by zero.
\n" ); document.write( " $\"x%2B1=0\"$
\n" ); document.write( " $\"x=-1\"$
\n" ); document.write( "This is the only solution.
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