document.write( "Question 1006100: How can i find a common difference for this arithmetic sequence?
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Algebra.Com's Answer #622230 by Theo(13342)![]() ![]() You can put this solution on YOUR website! give them all a common denominator and it might be easier to see.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(2) multiplied by sqrt(2) / sqrt(2) gives you sqrt(2)^2/sqrt(2) which is equal to 2/sqrt(2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "yoour sequence is now:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/sqrt(2), 2/sqrt(2),3sqrt(2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now it's easier to see that the common difference is 1/sqrt(2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1/sqrt(2) + 1/sqrt(2) = 2/sqrt(2) + 1/sqrt(2) = 3/sqrt(2)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |