document.write( "Question 1006083: The solution set in interval notation of the inequality 16x-x^3≥0 is: \r
\n" ); document.write( "\n" ); document.write( "A) [-4, 4]
\n" ); document.write( "B) (-∞, -2]U[0, 4)
\n" ); document.write( "C) (-∞, 0]U[1, 4)
\n" ); document.write( "D) (-∞, 4]
\n" ); document.write( "E) (-∞, -4]U[0, 4]
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Algebra.Com's Answer #622227 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"x%2816-x%5E2%29%3E=0\"
\n" ); document.write( "\"x%284%2Bx%29%284-x%29%3E=0\"\r
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\n" ); document.write( "\n" ); document.write( "Critical x values: -4,0,4;\r
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\n" ); document.write( "\n" ); document.write( "? (-infinity,-4] ?
\n" ); document.write( "(-)(-)(+)>=0
\n" ); document.write( "TRUE\r
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\n" ); document.write( "\n" ); document.write( "[-4,0] ?
\n" ); document.write( "Try -1.
\n" ); document.write( "(-1)(4-1)(4-(-1))=(-1)(3)(5)>=0
\n" ); document.write( "FALSE\r
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\n" ); document.write( "\n" ); document.write( "[0,4] ?
\n" ); document.write( "Try 1
\n" ); document.write( "1*(4+1)(4-1)=1*5*3>=0
\n" ); document.write( "TRUE\r
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\n" ); document.write( "\n" ); document.write( "[4, infinity) ?
\n" ); document.write( "5*(4+5)(4-5)=Negative>=0
\n" ); document.write( "FALSE\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solution set is (-infinity, -4] U [0,4].
\n" ); document.write( "Choice E.
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