document.write( "Question 1006074: How were going to transform a general equation of a circle to standard equation \n" ); document.write( "
Algebra.Com's Answer #622222 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
Complete the Squares for the variables.\r
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\n" ); document.write( "\n" ); document.write( "\"Ax%5E2%2BBx%2BCy%5E2%2BDy%2BE=0\" can be general form for a circle. Let this be changed because A and B would be equal if this is a circle.\r
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\n" ); document.write( "\n" ); document.write( "Instead, say \"highlight_green%28x%5E2%2BAx%2By%5E2%2BBy%2BC=0%29\", now the coefficients no longer being the same values as the previous general form equation. Continue working with this one.\r
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\n" ); document.write( "\"%28x%2B%28A%2F2%29%29%5E2%2B%28y%2BB%2F2%29%5E2=%28A%5E2%2BB%5E2%29%2F4-C\"
\n" ); document.write( "\"%28x%2BA%2F2%29%5E2%2B%28y%2BB%2F2%29%5E2=%28A%5E2%2BB%5E2%29%2F4-4C%2F4\"
\n" ); document.write( "\"highlight%28%28x%2BA%2F2%29%5E2%2B%28y%2BB%2F2%29%5E2=%28A%5E2%2BB%5E2-4C%29%2F4%29\"--------this is the standard form, equivalent to the general form.\r
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\n" ); document.write( "\n" ); document.write( "You would need to make some adjustments if the coefficients on x^2 and y^2 are not both equal to 1, before you start the conversion for your specific equation.\r
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\n" ); document.write( "\n" ); document.write( "The center of the circle would be at \"x=-A%2F2\", \"y=-B%2F2\", and the radius is \"sqrt%28A%5E2%2BB%5E2-4C%29%2F2\".
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