document.write( "Question 1006036: Traveling with the current, a boat covers in 4 hours a distance 2.4 times greater than traveling against the current. What is the speed of the boat in still water if the speed of the current is 1.5 mph?
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Algebra.Com's Answer #622177 by ankor@dixie-net.com(22740)\"\" \"About 
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Traveling with the current, a boat covers in 4 hours a distance 2.4 times greater than traveling against the current.
\n" ); document.write( " What is the speed of the boat in still water if the speed of the current is 1.5 mph?
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\n" ); document.write( "let s = boat speed in still water
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\n" ); document.write( "(s+1.5) = speed with the current
\n" ); document.write( "and
\n" ); document.write( "(s-1.5) = speed against
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\n" ); document.write( "Write a distance equation, dist = time * speed
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\n" ); document.write( "with dist = 2.4*against dist
\n" ); document.write( "4(s+1.5) = 2.4[4(s-1.5)]
\n" ); document.write( "4s + 6 = 2.4(4s - 6)
\n" ); document.write( "4s + 6 = 9.6s - 14.4
\n" ); document.write( "6 + 14.4 = 9.6s - 4s
\n" ); document.write( "20.4 = 5.6s
\n" ); document.write( "s = 20.4/5.6
\n" ); document.write( "s = 3.643 mph in still water
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\n" ); document.write( "See if that checks out
\n" ); document.write( " 4(3.643+1.5) = 2.4[4(3.643-1.5)]
\n" ); document.write( " 4(5.143) = 2.4*4(2.143)
\n" ); document.write( " 20.57 = 2.4(8.57)
\n" ); document.write( " 20.57 = 20.57
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