document.write( "Question 1005985: The perimeter of a standard-sized rectangular rug is 40 ft. The length is 2 ft longer than the width. Find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #622134 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+L+\"$ = length in ft
\n" ); document.write( "Let $\"+W+\"$ = width in ft
\n" ); document.write( "Let $\"+P+\"$ = perimeter of rug in ft
\n" ); document.write( "-----------------------------
\n" ); document.write( "The formula for perimeter is:
\n" ); document.write( " $\"+P+=+2L+%2B+2W+\"$
\n" ); document.write( "-----------------
\n" ); document.write( "given:
\n" ); document.write( " $\"+L+=+W+%2B+2+\"$
\n" ); document.write( " $\"+P+=+40+\"$
\n" ); document.write( "--------------
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"+P+=+2%2A%28+W+%2B+2+%29+%2B+2W+\"$
\n" ); document.write( " $\"+P+=+2W+%2B+4+%2B+2W+\"$
\n" ); document.write( " $\"+P+=+4W+%2B+4+\"$
\n" ); document.write( " $\"+40+=+4W+%2B+4+\"$
\n" ); document.write( " $\"+10+=+W+%2B+1+\"$
\n" ); document.write( " $\"+W+=+9+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+L+=+W+%2B+2+\"$
\n" ); document.write( " $\"+L+=+11+\"$
\n" ); document.write( "the rug's dimensions are:
\n" ); document.write( "9 x 11
\n" ); document.write( "-----------
\n" ); document.write( "check:
\n" ); document.write( " $\"+P+=+2L+%2B+2W+\"$
\n" ); document.write( " $\"+40+=+2%2A11+%2B+2%2A9+\"$
\n" ); document.write( " $\"+40+=+22+%2B+18+\"$
\n" ); document.write( " $\"+40+=+40+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );