document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004705>Question 1004705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice a first number decreased by a second number is -2. The first number increased by four times the second number is 35. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622124 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers x and y.  Then we have<BR>\n" );
document.write( "2x - y = -2 and<BR>\n" );
document.write( "x + 4y = 35<BR>\n" );
document.write( "Solve the second one for x and substitute it into the first equation and get<BR>\n" );
document.write( "x = -4y + 35  and then<BR>\n" );
document.write( "2(-4y + 35) - y = -2<BR>\n" );
document.write( "-8y + 70 - y = -2<BR>\n" );
document.write( "-9y + 70 = -2<BR>\n" );
document.write( "-9y = -72<BR>\n" );
document.write( "y = 8<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "x = -4(8) + 35 = 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );