document.write( "Question 1005498: Let \r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=1%2Fx%5E2\".\r
\n" ); document.write( "\n" ); document.write( "How do I show (just using the definition of the derivation, which is the difference quotient), that f is differentiable in R\{0} and that\r
\n" ); document.write( "\n" ); document.write( "f'(x)=\"-2%2Fx%5E3\" \r
\n" ); document.write( "\n" ); document.write( "for x as an element of R?\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help!
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Algebra.Com's Answer #622116 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=1%2Fx%5E2\"
\n" ); document.write( "\"f%28x%2Bh%29=1%2F%28x%2Bh%29%5E2\"
\n" ); document.write( "\"f%28x%2Bh%29-f%28x%29=1%2F%28x%2Bh%29%5E2-1%2Fx%5E2\"
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\n" ); document.write( "\"f%28x%2Bh%29-f%28x%29=%28x%5E2-%28x%2Bh%29%5E2%29%2F%28x%28x%2Bh%29%29%5E2\"
\n" ); document.write( "\"f%28x%2Bh%29-f%28x%29=%28x%5E2-%28x%5E2%2B2xh%2Bh%5E2%29%29%2Fx%28x%2Bh%29%29%5E2\"
\n" ); document.write( "\"f%28x%2Bh%29-f%28x%29=%28-2xh-h%5E2%29%2F%28x%28x%2Bh%29%29%5E2\"
\n" ); document.write( "\"%28f%28x%2Bh%29-f%28x%29%29%2Fh=%28-2x-h%29%2F%28x%28x%2Bh%29%29%5E2\"
\n" ); document.write( "So now taking the limit as h goes to zero,
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\n" ); document.write( "\"%28f%28x%2Bh%29-f%28x%29%29%2Fh=%28-2x%29%2Fx%5E4%29\"
\n" ); document.write( "\"%28f%28x%2Bh%29-f%28x%29%29%2Fh=-2%2Fx%5E3\"
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