document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005968>Question 1005968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In kick boxing, it is found that the force F needed to break a board varies inversely with the length L of the board. If it takes 30 pounds of force to break a board 2 feet long, how many pounds of force will it take it break a board that is 5 feet long? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622114 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An inverse relationship like this can be written as<BR>\n" );
document.write( "FL = k<BR>\n" );
document.write( "Here 30*2 = 60 = k<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "F(5) = 60<BR>\n" );
document.write( "F = 12 pounds of force </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );