document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005967>Question 1005967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One car travels 378 miles in same amount of time it takes a second car traveling 7 miles per hour slower than the first to go 336 miles. What are the speeds of the cars? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622111 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the slower car's rate, r.<BR>\n" );
document.write( "The faster one is then r+7.<BR>\n" );
document.write( "Since the times are equal, ad time = distance / rate, we have<BR>\n" );
document.write( "378/(r+7) = 336/r<BR>\n" );
document.write( "Cross multiply and get<BR>\n" );
document.write( "378r = 336r + 2352<BR>\n" );
document.write( "42r = 2352<BR>\n" );
document.write( "r = 56 mph<BR>\n" );
document.write( "r+7 = 63 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );