document.write( "Question 1005932: A car travels 380 miles averaging a certain speed. If the car had gone 5 mph faster the trip would have take 1 hour less. What was the average speed? \n" ); document.write( "
Algebra.Com's Answer #622102 by Alan3354(69443)\"\" \"About 
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A car travels 380 miles averaging a certain speed. If the car had gone 5 mph faster the trip would have take 1 hour less. What was the average speed?
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\n" ); document.write( "d = r*t
\n" ); document.write( "t = d/r
\n" ); document.write( "t = 380/r
\n" ); document.write( "t-1 = 380/(r+5)
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\n" ); document.write( "380/r - 1 = 380/(r+5)
\n" ); document.write( "(380 - r)/r = 380/(r+5)
\n" ); document.write( "(380 - r)*(r+5) = 380r
\n" ); document.write( "(r-380)*(r+5) = -380r
\n" ); document.write( "r^2 + 5r - 1900 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B5x%2B-1900+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%285%29%5E2-4%2A1%2A-1900=7625\".
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\n" ); document.write( " Discriminant d=7625 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-5%2B-sqrt%28+7625+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%285%29%2Bsqrt%28+7625+%29%29%2F2%5C1+=+41.1606229914325\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%285%29-sqrt%28+7625+%29%29%2F2%5C1+=+-46.1606229914325\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B5x%2B-1900\" can be factored:
\n" ); document.write( " \"1x%5E2%2B5x%2B-1900+=+%28x-41.1606229914325%29%2A%28x--46.1606229914325%29\"
\n" ); document.write( " Again, the answer is: 41.1606229914325, -46.1606229914325.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B5%2Ax%2B-1900+%29\"

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\n" ); document.write( "r =~ 41.16 mi/hr (Ignore the negative value)\r
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