document.write( "Question 12241: please help me with this problem.
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document.write( " 2/7x2&1/8x3=
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document.write( "The answers are.....6 & 1/28, 9/4, 1 & 23/28, or none of these. \n" );
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Algebra.Com's Answer #6221 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! 2/7x2&1/8x3= \n" ); document.write( "Begin by making the 2 1/8 an improper fraction = 17/8 \n" ); document.write( "Then put 3 in fraction form, 3/1 \n" ); document.write( "So now we have: \n" ); document.write( "2/7*17/8*3/1= \n" ); document.write( "Now we just multiply all the numerators together, and all denominators. \n" ); document.write( "2*17*3=102 \n" ); document.write( "7*8*1=56 \n" ); document.write( "So you have: 102/56 and when you simplify you get: \n" ); document.write( "1 46/56 simplify again = 1 23/28\r \n" ); document.write( "\n" ); document.write( "Hope this helps =) \n" ); document.write( " |