document.write( "Question 1005948: Is there a quick method you know to factor things out quickly? \r
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document.write( "like x^2-4x-12\r
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document.write( "How do I know just from quickly looking at it what it's gonna be? I've seen other people do this like how to set up the signs and know wat goes where. I think there is an easy way to solve these problems that I don't know about. I have to make a lot of guesses and then foil everything out until I get it right.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #622094 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Is there a quick method you know to factor things out quickly? \r \n" ); document.write( "\n" ); document.write( "like x^2-4x-12 \n" ); document.write( "------------------ \n" ); document.write( "It's trial and error. \n" ); document.write( "(ax + b)*(cx + d) = x^2-4x-12 \n" ); document.write( "There are things to notice, tho. \n" ); document.write( "The -12 --> b & d have different signs, one is + and one is negative. \n" ); document.write( "The -4x --> the negative term is larger. \n" ); document.write( "------------- \n" ); document.write( "It's not too hard when the coefficient of the x^2 = 1. \n" ); document.write( "a = c = 1 \n" ); document.write( "--- \n" ); document.write( "b*d = -12 \n" ); document.write( "b + d = -4 \n" ); document.write( "--- \n" ); document.write( "You find a combo of b & d that work. \n" ); document.write( "There are not many pairs of integers with a product of 12. \n" ); document.write( "Find the pair that differ by 4. \n" ); document.write( "1*12 NG \n" ); document.write( "2*6 \n" ); document.write( "3*4 NG \n" ); document.write( " \n" ); document.write( " |