document.write( "Question 1005930: Farmers in many province mill rice using a machine. One farmer use 3 machines A, B and C. When all three machines are working, 114 sacks can be milled in 1 week, when only A and B are working, 68 sacks of rice can be milled. When only B and C are working, 84 sacks can be milled in 1 week. How many sacks can produce in 1 week by each machine? Will the number of sacks milled per week \n" ); document.write( "
Algebra.Com's Answer #622089 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Unit for rate is SACKS per WEEK. Call their capital letters their corresponding rates.\r
\n" ); document.write( "\n" ); document.write( "Any combination of machines working at the same time is the sum of their rates.
\n" ); document.write( "\"system%28A%2BB%2BC=114%2CA%2BB=68%2CB%2BC=84%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the system any way you want or need.\r
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\n" ); document.write( "\n" ); document.write( "Here is a possible way.
\n" ); document.write( "\"A=114-B-C\"
\n" ); document.write( "-
\n" ); document.write( "\"system%28%28114-B-C%29%2BB=68%2CB%2BC=84%29\"\r
\n" ); document.write( "\n" ); document.write( "\"114-B-C%2BB=68\"
\n" ); document.write( "\"114-C=68\"
\n" ); document.write( "\"114-68=C\"
\n" ); document.write( "\"highlight%28C=46%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"B%2BC=84\"
\n" ); document.write( "\"B=84-C\"
\n" ); document.write( "\"B=84-46\"
\n" ); document.write( "\"highlight%28B=38%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can find A from those values.
\n" ); document.write( "\"highlight%28A=30%29\"
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