document.write( "Question 1005898: Consider the quadratic function y=kx(x-2)+3. If its optimum value is 4, find the value of k. \n" ); document.write( "
Algebra.Com's Answer #622066 by josgarithmetic(39618)\"\" \"About 
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\"y=kx%5E2-2kx%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"k%3C0\" and \"y=4\" where x is the middle value between the zeros.\r
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\n" ); document.write( "\n" ); document.write( "Finding zeros using formula for general solution of quadratic equation:
\n" ); document.write( "\"x=%282k%2B-+sqrt%284k%5E2-4k%2A3%29%29%2F%282k%29\"
\n" ); document.write( "D for discriminant,
\n" ); document.write( "\"x=%282k%2B-+sqrt%28D%29%29%2F%282k%29\"\r
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\n" ); document.write( "\n" ); document.write( "Middle x between the zeros is \"%282k%2B2k%29%2F%282%2A2k%29\"
\n" ); document.write( "\"4k%2F4k\"
\n" ); document.write( "\"highlight%281%29\"
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\n" ); document.write( "This means x=1 and y=4 is the maximum or \"optimum\" or VERTEX point for the function.\r
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\n" ); document.write( "\n" ); document.write( "\"4=k%2A1%281-2%29%2B3\" using the given original equation or function
\n" ); document.write( "\"4=k%28-1%29%2B3\"
\n" ); document.write( "\"4=-k%2B3\"
\n" ); document.write( "\"-4=k-3\"
\n" ); document.write( "\"k=-4%2B3\"
\n" ); document.write( "\"highlight%28k=-1%29\"
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