document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005925>Question 1005925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave a city and head in the same direction. <BR>\n" );
document.write( "After 3 hours, the faster car is 18 miles ahead of the <BR>\n" );
document.write( "slower car. The slower car has traveled 150 miles. Find <BR>\n" );
document.write( "the speeds of the two cars. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622060 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If in three hours the faster car is 18 miles ahead, then it reasons that it goes 6 miles per hour faster (6*3 = 18 miles).<BR>\n" );
document.write( "The slower car travels 150 miles in 3 hours, so its speed is<BR>\n" );
document.write( "r = d/t = 150 miles / 3 hours = 50 miles per hour<BR>\n" );
document.write( "The faster car is then traveling at 56 miles per hour. </SPAN>\n" );
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