document.write( "Question 1005908: A chemist wants to mix 10% alcohol solution and a 30% alcohol solution to make a 22% alcohol solution. How many ounces of each solution must be mixed to make 10 ounces of 22% solution
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Algebra.Com's Answer #622041 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let the amount of 10% solution be x. Then 10-x would be the amount of 30% solution. The set up looks like this: \n" ); document.write( "10x + 30(10-x) = 22(10) \n" ); document.write( "10x + 300 - 30x = 220 \n" ); document.write( "-20x + 300 = 220 \n" ); document.write( "-20x = -80 \n" ); document.write( "x = 4 ounces of 10% and then \n" ); document.write( "10-x = 6 ounces of 30% \n" ); document.write( " |