document.write( "Question 1005900: It is given that the axis of symmetry of the graph of the function y=x^2+kx+5=-3. Find the value of k. \n" ); document.write( "
Algebra.Com's Answer #622038 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "given that the axis of symmetry of the graph of the function \"y=x%5E2%2Bkx%2B5=-3\". Find the value of \"k\".\r
\n" ); document.write( "\n" ); document.write( "recall: The axis of symmetry of a parabola is the vertical line through the vertex. For a parabola in standard form, \"y+=+ax%5E2+%2B+bx+%2B+c\", the axis of symmetry has the equation \"x=+-b%2F2a\".\r
\n" ); document.write( "\n" ); document.write( "Note that \"-b%2F2a\" is also the x-coordinate of the vertex of the parabola. \r
\n" ); document.write( "\n" ); document.write( "if \"x%5E2%2Bkx%2B5=-3\", where \"a=1\" and \"b=k\" we have\r
\n" ); document.write( "\n" ); document.write( "\"x=+-k%2F2%2A1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+-k%2F2\" \r
\n" ); document.write( "\n" ); document.write( "\"2x=+-k\" \r
\n" ); document.write( "\n" ); document.write( "\"k=-2x\"....substitute in given equation and solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2Ax%2B5=-3\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%5E2%2B5=-3\"\r
\n" ); document.write( "\n" ); document.write( "\"-x%5E2%2B5=-3\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2B5=x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"8=x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%288%29\" \r
\n" ); document.write( "\n" ); document.write( "\"x=2sqrt%282%29\"
\n" ); document.write( "or \"x=-2sqrt%282%29\"\r
\n" ); document.write( "\n" ); document.write( "then, go back to \"k=-2x\", substitute values \"2sqrt%282%29\" and \"-2sqrt%282%29\" for \"x\" and find \"k\"\r
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\n" ); document.write( "\n" ); document.write( "\"k=-2x\"=>\"k=-2%2A2sqrt%282%29\"=>\"k=-4sqrt%282%29\"
\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"k=-2x\"=>\"k=+-2%2A%28-2sqrt%282%29%29\"=>\"k=4sqrt%282%29\"\r
\n" ); document.write( "\n" ); document.write( "so, your equations are:\r
\n" ); document.write( "\n" ); document.write( "\"y=x%5E2-4sqrt%282%29x%2B5\" or \"y=x%5E2%2B4sqrt%282%29x%2B5\"\r
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