document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005855>Question 1005855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two numbers such that if 18 is added to the first number it becomes twice the second number and 16 is added to the second number it becomes three times the first number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #622004 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=622004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find two numbers such that if 18 is added to the first number it becomes twice the second number and 16 is added to the second number it becomes three times the first number<BR>\n" );
document.write( "let number first is X <BR>\n" );
document.write( "than second number will be   y <BR>\n" );
document.write( "X+18= 2y<BR>\n" );
document.write( "x-2y=-18 (1)<BR>\n" );
document.write( "y+16=3x<BR>\n" );
document.write( "3x-y=16 (2)   by solving both equations  3x-6y=-54  and 3x-y=16<BR>\n" );
document.write( "5y=70   y=14   x= 10<BR>\n" );
document.write( "answer first number is 10 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );