document.write( "Question 1005853: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "Graph three members of the family of curves that have f(x)= -x + 1 as a common derivative.
\n" ); document.write( "

Algebra.Com's Answer #621997 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "f(x)= -x + 1 \r\n" );
document.write( "\r\n" );
document.write( "\"-x + 1\" is the sum of -x and 1.\r\n" );
document.write( "\r\n" );
document.write( "If we take the derivative of x² we get 2x.\r\n" );
document.write( "But we want -x, not 2x, So we must take the\r\n" );
document.write( "derivative of \"expr%28-1%2F2%29x%5E2\" to get -x.\r\n" );
document.write( "\r\n" );
document.write( "So we need the term \"expr%28-1%2F2%29x%5E2\".\r\n" );
document.write( "\r\n" );
document.write( "To get the 1 we must take the derivative of x.\r\n" );
document.write( "\r\n" );
document.write( "So the function \"expr%28-1%2F2%29x%5E2%2Bx\" would be such\r\n" );
document.write( "a function.\r\n" );
document.write( "\r\n" );
document.write( "However since the derivative of a constant is zero,\r\n" );
document.write( "we could have any constant added to that.  So here\r\n" );
document.write( "are some answers:\r\n" );
document.write( "\r\n" );
document.write( "\"expr%28-1%2F2%29x%5E2%2Bx%2B1\"\r\n" );
document.write( "\"expr%28-1%2F2%29x%5E2%2Bx-7\"\r\n" );
document.write( "\"expr%28-1%2F2%29x%5E2%2Bx%2B35\"\r\n" );
document.write( "\"expr%28-1%2F2%29x%5E2%2Bx-12\"\r\n" );
document.write( "\"expr%28-1%2F2%29x%5E2%2Bx%2B1000\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );