document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005795>Question 1005795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving a linear system with substitution: -12x+y=15, 3x+2y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621941 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From<BR>\n" );
document.write( "-12x+y=15 and <BR>\n" );
document.write( "3x+2y=3<BR>\n" );
document.write( "let us solve the first one for y and substitute it in...<BR>\n" );
document.write( "y = 12x + 15 and then<BR>\n" );
document.write( "3x + 2(12x + 15) = 3<BR>\n" );
document.write( "3x + 24x + 30 = 3<BR>\n" );
document.write( "27x = -27<BR>\n" );
document.write( "x = -1<BR>\n" );
document.write( "and substituting back we get<BR>\n" );
document.write( "3(-1)+2y=3<BR>\n" );
document.write( "-3 + 2y = 3<BR>\n" );
document.write( "2y = 6<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "The solution is (-1, 3). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );