document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005780>Question 1005780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tim&#8203;'s piggy bank contains dimes and nickels worth &#8203;$6.15. He has 77 coins in all. How many of each coin does Tim &#8203;have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621936 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of dimes and nickels, d and n.  Then we have<BR>\n" );
document.write( "d + n = 77 and the value equation is<BR>\n" );
document.write( "10d + 5n = 615  (we work in cents)<BR>\n" );
document.write( "Now multiply the top equation by five and subtract from the second...<BR>\n" );
document.write( "10d + 5n = 615<BR>\n" );
document.write( "-(5d + 5n = 385)<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "5d = 230<BR>\n" );
document.write( "d = 46 dimes<BR>\n" );
document.write( "n must be 31 nickels </SPAN>\n" );
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