document.write( "Question 1005778: Why is the domain of ln(14+x^2) ...(-inf,+inf)?\r
\n" ); document.write( "\n" ); document.write( "I thought with domain of ln we take what is inside and set that to zero, like so.
\n" ); document.write( "14+x^2 = 0
\n" ); document.write( "x^2 = -14
\n" ); document.write( "x = sqrt(-14)
\n" ); document.write( "x = DNE\r
\n" ); document.write( "\n" ); document.write( "so the domain doesn't exist.
\n" ); document.write( "Something I really dont get here
\n" ); document.write( "Please help
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #621935 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
When you solved 14+x^2 = 0 for x, you found that there were no real number solutions. There are no real numbers that make 14+x^2 = 0 true.\r
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\n" ); document.write( "\n" ); document.write( "It turns out that x^2+14 is ALWAYS positive. Regardless of whatever real number you pick for x. So x^2+14 is never negative.\r
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\n" ); document.write( "\n" ); document.write( "So it is impossible for ln(14+x^2) to be undefined.\r
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\n" ); document.write( "\n" ); document.write( "That is why the domain is the set of all real numbers, which in interval notation is (-inf,+inf) \n" ); document.write( "

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