document.write( "Question 1005734: 5. Solve the following equations\r
\n" ); document.write( "\n" ); document.write( "a) 3^m=81\r
\n" ); document.write( "\n" ); document.write( "b) (36p^4)12=24\r
\n" ); document.write( "\n" ); document.write( "c) 5^n×5^n+4=25\r
\n" ); document.write( "\n" ); document.write( "d) 4^7x/256=64^2x+2/16^2x−1
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Algebra.Com's Answer #621895 by Boreal(15235)\"\" \"About 
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3^m=81
\n" ); document.write( "m=4. One can take logs, but 3^2=9 and 9^2=81.
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\n" ); document.write( "(36p^4)12=24
\n" ); document.write( "36p^4=2
\n" ); document.write( "18p^4=1
\n" ); document.write( "18p^4-1=0
\n" ); document.write( "This can be p^4=(1/18)
\n" ); document.write( "p= +/- (1/18)^(1/4). That is two roots. You get the other complex ones by setting it up this way:
\n" ); document.write( "(sqrt(18)p^2+1)(sqrt(18) p^2-1)=0
\n" ); document.write( "the second is p^2=(1/sqrt(18) p=+/ - 1/18^(1/4)
\n" ); document.write( "The first is p= i +/- 1/18^(1/4)
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\n" ); document.write( "5^n×5^n+4=25
\n" ); document.write( "5^(2n+4)=25=5^2
\n" ); document.write( "Therefore, 2n+4=2, since the bases are equal. If we took logs to base 5, the base would disappear.
\n" ); document.write( "2n+4=2
\n" ); document.write( "n= -1
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\n" ); document.write( "4^7x/256=64^2x+2/16^2x−1
\n" ); document.write( "4^7x/4^4=4^(7x-4). That is the left side.
\n" ); document.write( "4^3(2x+2)/4^2(2x-1). That is the right side.
\n" ); document.write( "4^(7x-4)=4^(6x+6)/4^(4x-2)
\n" ); document.write( "log to base 4
\n" ); document.write( "7x-4= log 4 4^(6x+6-4x+2)=2x+8
\n" ); document.write( "5x=12
\n" ); document.write( "x=12/5
\n" ); document.write( "This checks.
\n" ); document.write( "The left side will be 50859008.46, which is 4^(84/5)-(20/5) or 4^(64/5)\r
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