document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005664>Question 1005664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=(x-2)(|x|+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621852 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x changes sign at 0.  The second factor is never non-positive, to always be positive, but the first factor can be less than 0 OR greater than 0, OR 0.\r<BR>\n" );
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