document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005648>Question 1005648</A>: <I><SPAN STYLE=\"word-break: break-all;\">   12 + 3/5f= 20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621835 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From\r<BR>\n" );
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document.write( "12 + (3/5)f = 20<BR>\n" );
document.write( "subtract 12 from both sides and get<BR>\n" );
document.write( "(3/5)f = 8<BR>\n" );
document.write( "Now multiply by 5/3 and get<BR>\n" );
document.write( "(5/3)(3/5)f = (5/3)(8)<BR>\n" );
document.write( "f = 40/3 = 13 1/3 </SPAN>\n" );
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