document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005652>Question 1005652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the diagonals of a rectangle are 2x+10 and 3x-5. find the measure of the diagonals </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621834 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621834\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the diagonals of a rectangle are congruent, we can set these amounts equal...we get\r<BR>\n" );
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document.write( "2x+10 = 3x-5<BR>\n" );
document.write( "Subtract 2x and add 5 to both sides and get<BR>\n" );
document.write( "x = 15<BR>\n" );
document.write( "Thus the diagonals both measure 40. </SPAN>\n" );
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