document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86046>Question 86046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay, I need someone's help PLEASE...I am supposed to add and express my answer in simplest form: x-13/x^2-x-12+3x-3/x^2-x-12 I answered this problem with 3/x-3 am I right or where did I go wrong? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62179 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-13)/(x^2-x-12)+(3x-3)/(x^2-x-12)<BR>\n" );
document.write( "The denominators are the same so combine the numerators to get:<BR>\n" );
document.write( "[4x-16]/(x^2-x-12)<BR>\n" );
document.write( "Factor to get:<BR>\n" );
document.write( "[4(x-4)]/[(x-4)(x+3)]<BR>\n" );
document.write( "Cancel the common (x-4) factor.<BR>\n" );
document.write( "= 4/(x+3)<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );