document.write( "Question 1005423: AGES OF FATHER AND HIS SON ARE IN RATIO OF 10:3 EIGHT YEARS AFTER THEIR AGES WOULD BE IN THE RATIO 12:5 FIND THEIR AGES \n" ); document.write( "

Algebra.Com's Answer #621788 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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AGES OF FATHER AND HIS SON ARE IN RATIO OF 10:3
\n" ); document.write( "let x = the multiplier
\n" ); document.write( "then
\n" ); document.write( "10x = the father's age
\n" ); document.write( "3x = the son's
\n" ); document.write( ":
\n" ); document.write( " EIGHT YEARS AFTER THEIR AGES WOULD BE IN THE RATIO 12:5
\n" ); document.write( " $\"%28%2810x%2B8%29%29%2F%28%283x%2B8%29%29\"$ = $\"12%2F5\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "5(10x+8) = 12(3x+8)
\n" ); document.write( "50x + 40 = 36x + 96
\n" ); document.write( "50x - 36x = 96 - 40
\n" ); document.write( "14x = 56
\n" ); document.write( "x = 56/14
\n" ); document.write( "x = 4 is the multiplier
\n" ); document.write( ":
\n" ); document.write( " FIND THEIR AGES
\n" ); document.write( "10(4) = 40 yrs is Dad's age
\n" ); document.write( "3(4) = 12 yrs is Son's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding their ages in 8 yrs
\n" ); document.write( "Dad's 48; Son's 20
\n" ); document.write( "48:20 reduces to 12:5
\n" ); document.write( " \n" ); document.write( "

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