document.write( "Question 1005536: A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt a full house consisting of three kings. \n" ); document.write( "
Algebra.Com's Answer #621749 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt a full house consisting of three kings. \n" ); document.write( "---- \n" ); document.write( "Pick 3 kings:: 4C3 = 4 ways \n" ); document.write( "Pick 2 of another card type:: 12*4C2 = 12*6 = 72 ways \n" ); document.write( "----- \n" ); document.write( "P(full house) = (4*72)/52C5 = 288/2598960 = 0.0001108.. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------- \n" ); document.write( " \n" ); document.write( " |