document.write( "Question 1005463: Using the formula h=-1/2gt^2+v(0)t+h(0) (the zero in the parens is lower/small beneath the letter) and g= gravitational constant and v = upward velocity from a starting height of h.
\n" ); document.write( " 1a. What is the height after three seconds of a penny dropped from the roof of the a tall building about 1250 feet tall?
\n" ); document.write( " 1b. After how many seconds does the penny hit the ground?
\n" ); document.write( " 2. What is the height after three seconds of a ball thrown from the roof of a building about 495 feet tall and is tossed upwards with a velocity of 10m/s?
\n" ); document.write( " 2b. After how many seconds does it hit the ground?
\n" ); document.write( " Thanks in advance. I think I have the answers but want to check the work done.
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Algebra.Com's Answer #621732 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
note when dropping an object from height, the initial velocity vo is 0. G is 16 for this problem, since given values are in feet.
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\n" ); document.write( "1a) h(3) = -8*3^2 + 0*3 + 1250 = 1178
\n" ); document.write( "after 3 seconds, the penny is 1178 feet above the ground
\n" ); document.write( "1b) 0 = -8t^2 +1250
\n" ); document.write( "t^2 = 156.25 and t = 12.5
\n" ); document.write( "after 12.5 seconds, the penny hits the ground
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\n" ); document.write( "the height of the building is given in feet, so convert vo = 10 m to feet/s, vo = 32.8 feet
\n" ); document.write( "2a) h(3) = -8*3^2 + 32.8*3 + 495 = 521.4
\n" ); document.write( "after three seconds, the ball is 521.4 feet above the ground.
\n" ); document.write( "2b) 0 = -8t^2 + 32.8t + 495
\n" ); document.write( "t^2 -4.1t - 61.875 = 0
\n" ); document.write( "t^2 -4.1t = 61.875
\n" ); document.write( "t^2 -4.1t + 4.2025 = 4.2025 + 61.875
\n" ); document.write( "(t - 2.05)^2 = 66.0775
\n" ); document.write( "t - 2.05 = 8.128806801 = approx 10.2
\n" ); document.write( "in 10.2 seconds the ball hits the ground
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\n" ); document.write( "here is the graph of 2b
\n" ); document.write( "\"graph%28300%2C+200%2C+-10%2C+12%2C+-2%2C+800%2C+-8x%5E2+%2B32.8x+%2B495%29\"\r
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