document.write( "Question 1005464: The sum of the 6th and 8th terms of an A.P is 142 . If the fourth term is 49 , (a) find the first term . (b) the common difference . (c) the sum of the first seven terms of the progression. \n" ); document.write( "
Algebra.Com's Answer #621718 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The sum of the 6th and 8th terms of an A.P is 142 . If the fourth term is 49 , (a) find the first term . (b) the common difference . (c) the sum of the first seven terms of the progression. \n" ); document.write( "---- \n" ); document.write( "6th term:: a(1)+5d \n" ); document.write( "8th term:: a(1)+7d \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "sum = 142 \n" ); document.write( "2*a(1) + 12d = 142 \n" ); document.write( "---- \n" ); document.write( "a(1) + 6d = 71 \n" ); document.write( "===== \n" ); document.write( "4th term:: a(1) + 3d = 49 \n" ); document.write( "-------- \n" ); document.write( "Equations: \n" ); document.write( "a(1) + 6d = 71 \n" ); document.write( "a(1) + 3d = 49 \n" ); document.write( "----- \n" ); document.write( "Subtract and solve for \"d\":: \n" ); document.write( "3d = 22 \n" ); document.write( "d = 22/3 \n" ); document.write( "---- \n" ); document.write( "Solve for a(1):: \n" ); document.write( "a(1) + 3d = 49 \n" ); document.write( "a(1) + 22 = 49 \n" ); document.write( "a(1) = 27 \n" ); document.write( "------------------ \n" ); document.write( "Sum the 1st 7 terms: \n" ); document.write( "S(7) = (7/2)(a(1)+a(7)] \n" ); document.write( "S(7) = (7/2)(27+71) \n" ); document.write( "S(7) = (7/2)(98) \n" ); document.write( "S(7) = 7*49 = 343 \n" ); document.write( "---------------\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |