document.write( "Question 1005336: the hypotenuse of a right triangle is 2 ft. longer than one leg and 4 ft. longer than the other leg. what are the dimensions of this triangle? \n" ); document.write( "
Algebra.Com's Answer #621708 by ikleyn(52794)\"\" \"About 
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document.write( "Let x = the length of the hypotenuse, in feet.\r\n" );
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document.write( "Then the legs are (x-2) ft and (x-4) ft,\r\n" );
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document.write( "and you have a quadratic equation\r\n" );
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document.write( "\"x-2%29%5E2\" + \"%28x-4%29%5E2\" = \"x%5E2\".\r\n" );
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document.write( "Simplify, and you will get\r\n" );
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document.write( "\"x%5E2+-+12x+%2B+20\" = \"0\".\r\n" );
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document.write( "There are two roots, 10 and 2.\r\n" );
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document.write( "The smaller doesn't fit. The greater does work.\r\n" );
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document.write( "Answer. 10 ft.\r\n" );
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