document.write( "Question 1005325: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "Show that the expression for the slope of the secant line through y=x^2 +3x at x=3 and x=3+h is msec=9+h. \r
\n" ); document.write( "\n" ); document.write( "Sketch the graph of y=x^2 +3x showing a sequence of secant lines described in the previous question as h approaches 0.
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Algebra.Com's Answer #621705 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The function is \"y=x%5E2+%2B3x\" .
\n" ); document.write( "The secant requested is the straight line that passes through points
\n" ); document.write( "\"A\" with \"system%28x%5BA%5D=3%2Cy%5BA%5D=3%5E2%2B3%2A3=9%2B9=18%29\" and
\n" ); document.write( "\"B\" with
\n" ); document.write( "The slope of secant \"AB\" is
\n" ); document.write( "\"m=%28y%5BB%5D-y%5BA%5D%29%2F%28x%5BB%5D-x%5BA%5D%29\" --> \"m=%2818%2B9h%2Bh%5E2-18%29%2F%283%2Bh-3%29\" --> \"m=%289h%2Bh%5E2%29%2Fh\" --> \"m=h%289%2Bh%29%2Fh\" --> \"highlight%28m=9%2Bh%29\"\r
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\n" ); document.write( "\n" ); document.write( "The graph with the secants for h=1, h=2, and h=3 are shown below.
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