document.write( "Question 1005396: a parkway 80 ft. wide is spanned by a parabolic arc 100 ft. long along the horizontal, if the parkway is in the center, how high must the vertex of the arch be in order to give a minimum clearance of 20 over the parkway? \n" ); document.write( "
Algebra.Com's Answer #621699 by KMST(5328)\"\" \"About 
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The parabola needed, drawn over a conveniently placed set of axes, with all measures in feet, looks like this:
\n" ); document.write( " The equation will be \"y=f%28x%29=ax%5E2%2Bk\" such that \"system%28f%2840%29=20%2Cf%2850%29=0%29\" .
\n" ); document.write( "\"system%28y=f%28x%29=ax%5E2%2Bk%2Cf%2840%29=20%2Cf%2850%29=0%29\"--->\"system%28y=f%28x%29=ax%5E2%2Bk%2Ca40%5E2%2Bk=20%2Ca50%5E2%2Bk=20%29\"--->\"system%28y=f%28x%29=ax%5E2%2Bk%2C1600a%2Bk=20%2C2500a%2Bk=0%29\"--->\"system%28y=f%28x%29=-x%5E2%2F45%2B500%2F9%2Ca=-1%2F45%2Ck=500%2F9%29\"
\n" ); document.write( "The height at the vertex (in feet) is \"f%280%29=highlight%28500%2F9=%2255.55+%28+rounded+%29%22%29\" .
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