document.write( "Question 1005264: In a PTA fund raising activity, couples who came where charge P400.00. However if only one parent came, he was charged P250.00. 59 people attended the activity and P12,150.00 was raised. How many couples attended?
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Algebra.Com's Answer #621688 by macston(5194)\"\" \"About 
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\n" ); document.write( "C=number of couples; S=number of singles
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\n" ); document.write( "2C+S=59
\n" ); document.write( "S=59-2C
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\n" ); document.write( "P400C+P250S=P12150
\n" ); document.write( "P400C+P250(59-2C)=P12150
\n" ); document.write( "P400C+P14750-P500C=P12150
\n" ); document.write( "-P100C=-P2600
\n" ); document.write( "C=26
\n" ); document.write( "ANSWER 1: There were 26 couples.
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\n" ); document.write( "S=59-2C
\n" ); document.write( "S=59-2(26)
\n" ); document.write( "S=59-52
\n" ); document.write( "S=7
\n" ); document.write( "ANSWER 2: There were 7 single parents.
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\n" ); document.write( "CHECK:
\n" ); document.write( "P400C+P250S=P12150
\n" ); document.write( "P400(26)+P250(7)=P12150
\n" ); document.write( "P10400+P1750=P12150
\n" ); document.write( "P12150=P12150
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