document.write( "Question 1005252: Divide 150 into three parts such that the second number is five-sixths the first and the third number is four fifths the second.
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Algebra.Com's Answer #621668 by ankor@dixie-net.com(22740)\"\" \"About 
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Divide 150 into three parts such that the second number is five-sixths the first and the third number is four fifths the second.
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\n" ); document.write( "Let a, b, c = the three parts, write an equation for each statement
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\n" ); document.write( " Divide 150 into three parts
\n" ); document.write( "a + b + c = 150
\n" ); document.write( "such that the second number is five-sixths the first
\n" ); document.write( "b = \"5%2F6\"a
\n" ); document.write( "or multiply both sides by 6/5
\n" ); document.write( "a = \"6%2F5\"b
\n" ); document.write( "and the third number is four fifths the second.
\n" ); document.write( "c = \"4%2F5\"b
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\n" ); document.write( "Replace a and c in the first equation
\n" ); document.write( "\"6%2F5\"b + b + \"4%2F5\"b = 150
\n" ); document.write( "multiply equation by 5, cancel the denominators
\n" ); document.write( "6b + 5b + 4b = 5(150)
\n" ); document.write( "15b = 750
\n" ); document.write( "b = 750/15
\n" ); document.write( "b = 50 is the 2nd number
\n" ); document.write( "then
\n" ); document.write( "a = \"6%2F5\"*50
\n" ); document.write( "a = 60
\n" ); document.write( "and
\n" ); document.write( "c = \"4%2F5\"*50
\n" ); document.write( "c = 40
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\n" ); document.write( "They add up to 150.
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