document.write( "Question 1005252: Divide 150 into three parts such that the second number is five-sixths the first and the third number is four fifths the second.
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Algebra.Com's Answer #621668 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Divide 150 into three parts such that the second number is five-sixths the first and the third number is four fifths the second. \n" ); document.write( ": \n" ); document.write( "Let a, b, c = the three parts, write an equation for each statement \n" ); document.write( ": \n" ); document.write( " Divide 150 into three parts \n" ); document.write( "a + b + c = 150 \n" ); document.write( "such that the second number is five-sixths the first \n" ); document.write( "b = \n" ); document.write( "or multiply both sides by 6/5 \n" ); document.write( "a = \n" ); document.write( "and the third number is four fifths the second. \n" ); document.write( "c = \n" ); document.write( ": \n" ); document.write( "Replace a and c in the first equation \n" ); document.write( " \n" ); document.write( "multiply equation by 5, cancel the denominators \n" ); document.write( "6b + 5b + 4b = 5(150) \n" ); document.write( "15b = 750 \n" ); document.write( "b = 750/15 \n" ); document.write( "b = 50 is the 2nd number \n" ); document.write( "then \n" ); document.write( "a = \n" ); document.write( "a = 60 \n" ); document.write( "and \n" ); document.write( "c = \n" ); document.write( "c = 40 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "They add up to 150. \n" ); document.write( " |