document.write( "Question 1005282: Three years ago, Mary was three times as old as Ann. Three years hence she will be twice as old Find the present age of eac. \n" ); document.write( "
Algebra.Com's Answer #621661 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let m = Mary's present age \n" ); document.write( "let a = Ann's \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement, simplify \n" ); document.write( ": \n" ); document.write( "Three years ago, Mary was three times as old as Ann. \n" ); document.write( "m - 3 = 3(a - 3) \n" ); document.write( "m - 3 = 3a - 9 \n" ); document.write( "m = 3a - 9 + 3 \n" ); document.write( "m = 3a - 6 \n" ); document.write( " Three years hence she will be twice as old \n" ); document.write( "m + 3 = 2(a + 3) \n" ); document.write( "m + 3 = 2a + 6 \n" ); document.write( "m = 2a + 6 - 3 \n" ); document.write( "m = 2a + 3 \n" ); document.write( ": \n" ); document.write( "m = m, therefore we can write the equation \n" ); document.write( "3a - 6 = 2a + 3 \n" ); document.write( "3a - 2a = 3 + 6 \n" ); document.write( "a = 9 yrs old is Ann \n" ); document.write( ": \n" ); document.write( "Find m using m = 2a + 3 \n" ); document.write( "m = 2(9) + 3 \n" ); document.write( "m = 21 yrs is Mary \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm our solution in the first statement equation \n" ); document.write( "21 - 3 = 3(9 - 3) \n" ); document.write( "18 = 3(6) \n" ); document.write( " |