document.write( "Question 1005282: Three years ago, Mary was three times as old as Ann. Three years hence she will be twice as old Find the present age of eac. \n" ); document.write( "
Algebra.Com's Answer #621661 by ankor@dixie-net.com(22740)\"\" \"About 
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let m = Mary's present age
\n" ); document.write( "let a = Ann's
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\n" ); document.write( "Write an equation for each statement, simplify
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\n" ); document.write( "Three years ago, Mary was three times as old as Ann.
\n" ); document.write( "m - 3 = 3(a - 3)
\n" ); document.write( "m - 3 = 3a - 9
\n" ); document.write( "m = 3a - 9 + 3
\n" ); document.write( "m = 3a - 6
\n" ); document.write( " Three years hence she will be twice as old
\n" ); document.write( "m + 3 = 2(a + 3)
\n" ); document.write( "m + 3 = 2a + 6
\n" ); document.write( "m = 2a + 6 - 3
\n" ); document.write( "m = 2a + 3
\n" ); document.write( ":
\n" ); document.write( "m = m, therefore we can write the equation
\n" ); document.write( "3a - 6 = 2a + 3
\n" ); document.write( "3a - 2a = 3 + 6
\n" ); document.write( "a = 9 yrs old is Ann
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\n" ); document.write( "Find m using m = 2a + 3
\n" ); document.write( "m = 2(9) + 3
\n" ); document.write( "m = 21 yrs is Mary
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\n" ); document.write( "Confirm our solution in the first statement equation
\n" ); document.write( "21 - 3 = 3(9 - 3)
\n" ); document.write( "18 = 3(6)
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