document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005259>Question 1005259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 times its width. If the width is diminished by one meter and its length increased by 3 meters, the area will be increased by 72 sq. meters. What are the original dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621657 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 times its width.<BR>\n" );
document.write( "L = 3W<BR>\n" );
document.write( " If the width is diminished by one meter and its length increased by 3 meters, the area will be increased by 72 sq. meters.<BR>\n" );
document.write( "(L+3)*(W-1) = LW + 72<BR>\n" );
document.write( "Replace L with 3W<BR>\n" );
document.write( "(3W+3)*(W-1) = 3W(W) + 72<BR>\n" );
document.write( "FOIL the left side<BR>\n" );
document.write( "3W^2 - 3W + 3W - 3 = 3W^2 + 72<BR>\n" );
document.write( "So you get<BR>\n" );
document.write( "3W^2 - 3 = 3W^2 + 72<BR>\n" );
document.write( "obviously this will not fly, problem is not solvable \r<BR>\n" );
document.write( "\n" );
document.write( " <BR>\n" );
document.write( "What are the original dimensions of the rectangle? <BR>\n" );
document.write( ":\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );