document.write( "Question 1005257: log in base 1/3 *(1/27)= x
\n" ); document.write( "What's the solution for x?
\n" ); document.write( "Can you please write also the solution step-by-step?
\n" ); document.write( "Thanks in advance
\n" ); document.write( "

Algebra.Com's Answer #621611 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "log in base 1/3 *(1/27)= x
\n" ); document.write( "What's the solution for x?
\n" ); document.write( "Can you please write also the solution step-by-step?
\n" ); document.write( "Thanks in advance
\n" ); document.write( "
If this is what you meant: \"log+%281%2F3%2C+%281%2F27%29%29+=+x\", then read on.
\n" ); document.write( "\"%281%2F3%29%5Ex+=+1%2F27\" ----------- Converting to EXPONENTIAL form
\n" ); document.write( "\"%283%5E-1%29%5Ex+=+3%5E-+3\"----- Converting \"1%2F3\", and \"1%2F27\" to base 3
\n" ); document.write( "\"3%5E%28-+x%29+=+3%5E+-+3\" -------- Applying the following law: \"%28a%5Eb%29%5Ec\" = \"a%5E%28bc%29\"
\n" ); document.write( "- x = - 3 ------------- Bases are equal and so are their exponents
\n" ); document.write( "\"x+=+%28-+3%29%2F%28-+1%29\", or \"highlight_green%28x+=+3%29\" \n" ); document.write( "
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