document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005267>Question 1005267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of any line that you like but must be perpendicular to the line whose x-intercept is 1 and y-intercept is is 1/2.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621577 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "If the line cuts the y axis at 1/2<BR>\n" );
document.write( "and the x axis at 1<BR>\n" );
document.write( "Then the gradient = -1/2<BR>\n" );
document.write( "Mid point of (1,0) and (0, 1/2)<BR>\n" );
document.write( "= (1/2, 1/4)<BR>\n" );
document.write( "Perpendicular's gradient = 2<BR>\n" );
document.write( "Lines that are perpendicular<BR>\n" );
document.write( "to one another have gradients that<BR>\n" );
document.write( "multiply together to give -1<BR>\n" );
document.write( "m1 x m2 = -1<BR>\n" );
document.write( "-1/2 x  2 = -1<BR>\n" );
document.write( "Using the equation of the line<BR>\n" );
document.write( "y - b = m(x - a)<BR>\n" );
document.write( "with m = 2<BR>\n" );
document.write( "(a,b) = (1/2, 1/4)<BR>\n" );
document.write( "y - 1/4 = 2(x - 1/2)<BR>\n" );
document.write( "y - 1/4 = 2x - 1<BR>\n" );
document.write( "y = -2x - 1 + 1/4<BR>\n" );
document.write( "y = -2x -3/4<BR>\n" );
document.write( "or multiply through by 4<BR>\n" );
document.write( "4y = -8x - 3<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );