document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005257>Question 1005257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log in base 1/3 *(1/27)= x <BR>\n" );
document.write( "What's the solution for x? <BR>\n" );
document.write( "Can you please write also the solution step-by-step?<BR>\n" );
document.write( "Thanks in advance  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621572 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i think what you are saying is log of (1/27) to the base of (1/3) = x\r<BR>\n" );
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document.write( "in algebra.com that would be written as log(1/3,1/27) = x\r<BR>\n" );
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document.write( "in fact, place three opening brackets \"{\" in front and 3 closing brackets \"}\" in back and the statement log(1/3,1/27) = x looks like <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%281%2F3%2C1%2F27%29+=+x ALIGN=MIDDLE  ALT=\"log%281%2F3%2C1%2F27%29+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "the general form is log(a,b) = c means log of b to the base of a = c\r<BR>\n" );
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document.write( "the basic definition of logs states:\r<BR>\n" );
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document.write( "log(a,b) = c if and only if a^c = b\r<BR>\n" );
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document.write( "using that basic definition and applying it to the case where a = 1/3, and b = 1/27 and c = x, you get:\r<BR>\n" );
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document.write( "log(1/3,1/27) = x if and only if (1/3)^x = (1/27)\r<BR>\n" );
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document.write( "this statement is true when the value of x = 3.\r<BR>\n" );
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document.write( "to confirm, replace x with the value of 3 in the equation log(1/3,1/27) = x, and you get:\r<BR>\n" );
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document.write( "log(1/3,1/27) = 3\r<BR>\n" );
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document.write( "this is true if and only if (1/3)^3 = (1/27).\r<BR>\n" );
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document.write( "evaluate this statement and you get 1/27 = 1/27 which is true.\r<BR>\n" );
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document.write( "this confirms the value of x = 3 is the solution to your problem.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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