document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85999>Question 85999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me with this probability question. It is from textbook Algebra II by A Beka Book. I tried to use the solution provided for question 83651 but couldn't solve it.<BR>\n" );
document.write( "In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.<BR>\n" );
document.write( "What is the probability of getting-<BR>\n" );
document.write( "a)1 green M&M if only 1 is taken at a time?<BR>\n" );
document.write( "b)3 yellow M&M's if 3 are taken at a time?<BR>\n" );
document.write( "c)1 brown and 2 orange M&M's if 3 are taken at a time?<BR>\n" );
document.write( "Thank you so much for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62156 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange.<BR>\n" );
document.write( "What is the probability of getting-<BR>\n" );
document.write( "a)1 green M&M if only 1 is taken at a time?<BR>\n" );
document.write( "P(1 green) = 3/20<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "b)3 yellow M&M's if 3 are taken at a time?<BR>\n" );
document.write( "P(3 yellow) = 6C3/20C3 = [6*5*4/1*2*3]/[20*19*18/1*2*3]<BR>\n" );
document.write( "=0.01754<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "c)1 brown and 2 orange M&M's if 3 are taken at a time?<BR>\n" );
document.write( "P(1 brown and 2 orange) = [P(1 brown) + P(2 orange)]/20C3<BR>\n" );
document.write( "=[P(1 brown)*P(2 orange|1 brown)]/ 20C3<BR>\n" );
document.write( "=[(5/20)*2C2/19C2]/20C3<BR>\n" );
document.write( "=[(1/4)*(1/171)]/1140<BR>\n" );
document.write( "=[0.001462]/1140<BR>\n" );
document.write( "=0.00000128<BR>\n" );
document.write( "==========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );