document.write( "Question 1005089: The length of a rectangle is 3 cm more than the width. If the width is increased by 2 cm and the length is decreased by 1 cm, the figure becomes a square with an area of sq. cms. What is the original perimeter of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #621554 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You omitted the value for the resulting area of the square-formed rectangle after its changes.
\n" ); document.write( "Just calling this area, A,\r
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\n" ); document.write( "\n" ); document.write( "L and w for original dimensions,
\n" ); document.write( "\"L=w%2B3\"
\n" ); document.write( "-
\n" ); document.write( "\"%28w%2B2%29%28L-1%29=A\"
\n" ); document.write( "\"%28w%2B2%29%28w%2B3-1%29=A\"
\n" ); document.write( "\"%28w%2B2%29%28w%2B2%29=A\"
\n" ); document.write( "\"w%2B2=sqrt%28A%29\"
\n" ); document.write( "\"highlight_green%28w=-2%2Bsqrt%28A%29%29\" and this means \"highlight_green%28L=1%2Bsqrt%28A%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "You can calculate the original perimeter.
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