document.write( "Question 1005187: How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution. \n" ); document.write( "
Algebra.Com's Answer #621528 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x liters of 20% \n" ); document.write( ".20x+30(.50)=(x+30)(.40) \n" ); document.write( ".20x+15=.40x + 12 \n" ); document.write( "-.20x= -3 \n" ); document.write( "x=15 liters \n" ); document.write( "15*(.20 pure acid)=3 liters \n" ); document.write( "30*(.50 pure acid)=15 liters \n" ); document.write( "That is 18 liters pure acid \n" ); document.write( "That is 45 liters solution *0.45 pure acid=18 liters. \n" ); document.write( "The answer is 15 liters \n" ); document.write( " \n" ); document.write( " |