document.write( "Question 1005187: How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution. \n" ); document.write( "
Algebra.Com's Answer #621528 by Boreal(15235)\"\" \"About 
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x liters of 20%
\n" ); document.write( ".20x+30(.50)=(x+30)(.40)
\n" ); document.write( ".20x+15=.40x + 12
\n" ); document.write( "-.20x= -3
\n" ); document.write( "x=15 liters
\n" ); document.write( "15*(.20 pure acid)=3 liters
\n" ); document.write( "30*(.50 pure acid)=15 liters
\n" ); document.write( "That is 18 liters pure acid
\n" ); document.write( "That is 45 liters solution *0.45 pure acid=18 liters.
\n" ); document.write( "The answer is 15 liters
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