document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005161>Question 1005161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bina spent 1/3 of an amount on candy. he is left with $70. how much did he have initially?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621497 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well if he spent 1/3 of his money, then he must still have 2/3 of his money.<BR>\n" );
document.write( "We can write this as<BR>\n" );
document.write( "(2/3)x = 70<BR>\n" );
document.write( "Now multiply both sides by 3/2 and get<BR>\n" );
document.write( "x = $105 </SPAN>\n" );
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