document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005041>Question 1005041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The side of a square house is 24 feet long and the house is located on a lot which is 50 feet longer than it is wide the perimeter of the lot is 20 feet more than five times the perimeter of the house find the length of the lot </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #621471 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=621471\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the lot's width, w.  Then its length is w + 50.<BR>\n" );
document.write( "Perimeter = 2L + 2W = 2(w + 50) + 2w = 5(4(24)) + 20<BR>\n" );
document.write( "Then we get<BR>\n" );
document.write( "2w + 100 + 2w = 5(96) + 20<BR>\n" );
document.write( "4w + 100 = 480 + 20 = 500<BR>\n" );
document.write( "4w = 400<BR>\n" );
document.write( "w = 100 feet<BR>\n" );
document.write( "The length is 50 feet more, or<BR>\n" );
document.write( "150 feet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );